Question

Find the greatest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively.

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Answer

To determine the greatest number that divides both 2011 and 2623, leaving remainders 9 and 5 respectively, follow these steps:

  1. Understand the problem:

    • When a number divides 2011 leaving a remainder of 9, it means $$ 2011 - 9 = 2002 $$ is divisible by that number.
    • Similarly, when the same number divides 2623 leaving a remainder of 5, it means $$ 2623 - 5 = 2618 $$ is divisible by the required number.
  2. Form the equations:

    • We need to find the number that divides 2002 and 2618 perfectly.
  3. Calculate the H.C.F. using Euclid’s division lemma:

    • First, apply Euclid's algorithm to find the H.C.F. of 2002 and 2618.
    • Perform the division steps:
      • $$ 2618 = 2002 \times 1 + 616 $$
      • $$ 2002 = 616 \times 3 + 154 $$
      • $$ 616 = 154 \times 4 + 0 $$
  4. Identify the H.C.F.:

    • The division steps conclude with a remainder of 0 when 154 is the remainder.
    • Therefore, the H.C.F. of 2002 and 2618 is 154.

**Hence, the greatest number that divides both 2011 and 2623 leaving the respective remainders is 154.


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