Find the greatest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively.
Question
Find the greatest number which divides 2011 and 2623 leaving remainders 9 and 5 respectively.
✨ Free AI Tools for You
Powered by Chatterbot AI
Answer
To determine the greatest number that divides both 2011 and 2623, leaving remainders 9 and 5 respectively, follow these steps:
-
Understand the problem:
- When a number divides 2011 leaving a remainder of 9, it means $$ 2011 - 9 = 2002 $$ is divisible by that number.
- Similarly, when the same number divides 2623 leaving a remainder of 5, it means $$ 2623 - 5 = 2618 $$ is divisible by the required number.
-
Form the equations:
- We need to find the number that divides 2002 and 2618 perfectly.
-
Calculate the H.C.F. using Euclid’s division lemma:
- First, apply Euclid's algorithm to find the H.C.F. of 2002 and 2618.
- Perform the division steps:
- $$ 2618 = 2002 \times 1 + 616 $$
- $$ 2002 = 616 \times 3 + 154 $$
- $$ 616 = 154 \times 4 + 0 $$
-
Identify the H.C.F.:
- The division steps conclude with a remainder of 0 when 154 is the remainder.
- Therefore, the H.C.F. of 2002 and 2618 is 154.
**Hence, the greatest number that divides both 2011 and 2623 leaving the respective remainders is 154.
India's 1st AI Doubt Solver for CBSE, JEE, and NEET
Ask a Question for Freeand then it's just ₹212 a month