Question

Give the output of the following when num1 =4, num2 =3, num3=2

a)

num1 += num2 + num3 
print (num1)

b)

num1 = num1 ** (num2 + num3) 
print (num1)

c)

num1 **= num2 + num3

d)

num1 = '5' + '5' 
print (num1)

e)

print (4.00/(2.0+2.0))

f)

num1 =2 + 9 ((3 * 12)-8) / 10
print (num1)

g)

num1 = 24 // 4 // 2

h)

num1 = float(10)
print (num1)

i)

num1 = int('3.14') 
print (num1)

j)

print('Bye' == 'BYE')

k)

print(10 != 9 and 20 >= 20)

l)

print (10 + 6 * 2  ** 2! = 9 / / 4-3 and 29 >= 29 / 9)

m)

print(5 % 10 + 10 < 50 and 29 <= 29)

n)

print (( 0 < 6) or (not(10==6) and (10 < 0)))

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Answer

Let's determine the output of each code segment.

a)

num1 += num2 + num3 
print(num1)`
  • Initial Values: num1 = 4, num2 = 3, num3 = 2

  • Operation: num1 += 3 + 2num1 = num1 + 5num1 = 4 + 5num1 = 9

  • Output: 9

b)

num1 = num1 ** (num2 + num3) 
print(num1)
  • Values from (a): num1 = 9, num2 = 3, num3 = 2

  • Operation: num1 ** (3 + 2)9 ** 559049

  • Output: 59049

c)

num1 **= num2 + num3
  • Values from (a): num1 = 9, num2 = 3, num3 = 2

  • Operation: num1 **= 3 + 2num1 = 9 ** 5num1 = 59049

  • No Print Statement, so no output.

d)

num1 = '5' + '5' 
print(num1)
  • Operation: '5' + '5'"55"

  • Output: "55"

e)

print(4.00 / (2.0 + 2.0))
  • Operation: 4.00 / 4.01.0

  • Output: 1.0

f)

num1 = 2 + 9 * ((3 * 12) - 8) / 10
print(num1)
  • Operation: Assuming a typo, it should be: 2 + 9 * (36 - 8) / 102 + 9 * 28 / 102 + 252 / 102 + 25.227.2

  • Output: 27.2

g)

num1 = 24 // 4 // 2
  • Operation: 24 // 4 // 26 // 23

  • Output: Not printed.

h)

num1 = float(10)
print(num1)`
  • Operation: float(10)10.0

  • Output: 10.0

i)

num1 = int('3.14')
print(num1)`
  • Operation: Attempting to convert 3.14, a string with a decimal, to an integer will raise a ValueError.

  • Output: Error ValueError: invalid literal for int() with base 10: '3.14'

j)

print('Bye' == 'BYE')
  • Operation: 'Bye' is not equal to 'BYE' because strings are case-sensitive.

  • Output: False

k)

print(10 != 9 and 20 >= 20)
  • Operation: 10 != 9 evaluates to True, 20 >= 20 evaluates to True. Hence, True and TrueTrue

  • Output: True

l)

print(10 + 6 * 2  ** 2 != 9 // 4 - 3 and 29 >= 29 / 9)
  • Operation:

    • 6 * 2 ** 26 * 424

    • 10 + 2434

    • 9 // 42

    • 2 - 3-1

    • 34 != -1True

    • 29 / 93.222

    • 29 >= 3.222True

    • True and TrueTrue

  • Output: True

m)

print(5 % 10 + 10 < 50 and 29 <= 29)
  • Operation:

    • 5 % 105

    • 5 + 1015

    • 15 < 50True

    • 29 <= 29True

    • True and TrueTrue

  • Output: True

n)

print((0 < 6) or (not(10 == 6) and (10 < 0)))
  • Operation:

    • (0 < 6)True

    • 10 == 6False

    • not(False)True

    • (10 < 0)False

    • True and FalseFalse

    • True or FalseTrue

  • Output: True

Summary of Outputs:

a) 9

b) 59049

c) No output as there's no print statement.

d) "55"

e) 1.0

f) 27.2

g) No output as there's no print statement.

h) 10.0

i) Error: ValueError: invalid literal for int() with base 10: '3.14'

j) False

k) True

l) True

m) True

n) True


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