Question

Given that the number $\overline{35}$ a 64 is divisible by 3, where a is a digit, what are the possible values of a?

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Answer

Given that the number $\overline{35 \text{a} 64}$ is divisible by 3, we need to determine the possible values of the digit $a$.

  1. Condition for divisibility: For any number to be divisible by 3, the sum of its digits must also be divisible by 3.

  2. Sum of the given number’s digits:

    • The digits of our number are: $3, 5, a, 6,$ and $4$.
    • Adding these digits, we get: $$ 3 + 5 + a + 6 + 4 = 18 + a $$
  3. Divisibility by 3:

    • The expression $18 + a$ must be divisible by 3.
    • Since 18 is already divisible by 3, adding $a$ to it means $a$ itself must be divisible by 3 to maintain the overall divisibility.
  4. Possible values of $a$:

    • The digits from 0 to 9 that are divisible by 3 are 0, 3, 6, and 9.

Therefore, the possible values of $a$ are: $$ \boxed{0, 3, 6, 9} $$


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