How is math.ceil(89.7) different from math.floor (89.7)?

Observe the following programs carefully, and identify the error:

a)

def create (text, freq):
    for i in range (1, freq):
        print text

create(5) # function call

b)

from math import sqrt, ceil

def calc():
    print cos (0)

calc() #function call

c)

mynum = 9

def add9():
   mynum = mynum + 9

add9() # function call

d)

def findValue(val1 = 1.1, val2, val3):
    final = (val2 + val3) / vall1
    print(final)

findValue() # function call

e)

def greet():
    return("Good morning")

greet() = message # function call

If $\vec{a} = \hat{i} + \hat{j} - \hat{k}$, $\vec{b} = \hat{i} - \hat{j} + \hat{k}$, and $\vec{c}$ is a unit vector perpendicular to the vector $\vec{a}$ and coplanar with $\vec{a}$ and $\vec{b}$, then a unit vector $\vec{d}$ perpendicular to both $\vec{a}$ and $\vec{c}$ is:

A $\quad \frac{1}{\sqrt{6}}(2 \hat{i} - \hat{j} + \hat{k})$ B $\frac{1}{\sqrt{2}}(\hat{j} + \hat{k})$ C $\frac{1}{\sqrt{2}}(\hat{i} + \hat{j})$ D $\frac{1}{\sqrt{2}}(\hat{i} + \hat{k})$

How is built-in function pow() function different from function math.pow() ? Explain with an example.

If $\frac{x-p}{x^2-3x+2}$ takes all real values for $x \in \mathbb{R}$, then the range of $p$ is

Show that the locus of a point such that the ratio of its distances from two given points is a constant is a circle. Hence, show that this circle cannot pass through the given points.