Take a two-digit number ab and reverse its digits. If the difference between ab and the new number is cd, then by which number is cd divisible?
Question
Take a two-digit number ab and reverse its digits. If the difference between ab and the new number is cd, then by which number is cd divisible?
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Answer
The correct option is A: 9
Let's denote a two-digit number as $ab$. This number can be expressed mathematically as: $$ \text{Original number} = 10a + b $$
When the digits are reversed, the new number becomes $ba$, which can be written as: $$ \text{Number obtained by reversing the digits} = 10b + a $$
The problem states that the difference between the original number and the reversed number is $cd$. Let's calculate that difference:
$$ \begin{aligned} cd &= (10a + b) - (10b + a) \ &= 10a + b - 10b - a \ &= (10a - a) + (b - 10b) \ &= 9a - 9b \ &= 9(a - b) \end{aligned} $$
From the above calculation, it is clear that $cd$ is always a multiple of 9.
Therefore, $cd$ is divisible by 9.
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