Question

The sum of digits of a two-digit number is 9. The digit at ten's place is twice the digit at unit's place. Then the number is

  • 36
  • 54
  • 63
  • 45

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Answer

Correct Option: C - 63

Let's break down the solution to find the number:

  1. Let the digit at the unit's place be $ x $.

  2. The digit at the ten's place is $ 2x $ since it is given that it is twice the unit digit.

  3. According to the problem, the sum of the digits is 9:

    $$ 2x + x = 9 $$

  4. Simplifying the equation:

    $$ 3x = 9 $$

  5. Solve for $ x $:

    $$ x = \frac{9}{3} = 3 $$

  6. Therefore, the digit at the unit's place is 3, and the digit at the ten's place is:

    $$ 2x = 2 \times 3 = 6 $$

  7. Thus, the number is 63.

So, the correct answer is 63.


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