The sum of digits of a two-digit number is 9. The digit at ten's place is twice the digit at unit's place. Then the number is 36 54 63 45
Question
The sum of digits of a two-digit number is 9. The digit at ten's place is twice the digit at unit's place. Then the number is
- 36
- 54
- 63
- 45
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Answer
Correct Option: C - 63
Let's break down the solution to find the number:
-
Let the digit at the unit's place be $ x $.
-
The digit at the ten's place is $ 2x $ since it is given that it is twice the unit digit.
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According to the problem, the sum of the digits is 9:
$$ 2x + x = 9 $$
-
Simplifying the equation:
$$ 3x = 9 $$
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Solve for $ x $:
$$ x = \frac{9}{3} = 3 $$
-
Therefore, the digit at the unit's place is 3, and the digit at the ten's place is:
$$ 2x = 2 \times 3 = 6 $$
-
Thus, the number is 63.
So, the correct answer is 63.
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