Question

Two friends decide who gets the last slice of a cake by flipping a coin five times. The first person to win three flips wins the cake. An input of 1 means player 1 wins a flip, and a 2 means player 2 wins a flip. Design an algorithm to determine who takes the cake.

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Answer

Here is a pseudocode to determine who takes the cake:

INITIALIZE player1_wins to 0
INITIALIZE player2_wins to 0
REPEAT 5 TIMES
    PRINT "Enter the result of the flip (1 for player 1, 2 for player 2):"
    INPUT flip_result
    IF flip_result == 1 THEN
        INCREMENT player1_wins
        IF player1_wins == 3 THEN
            PRINT "Player 1 wins the cake!"
            EXIT LOOP
    ELSE IF flip_result == 2 THEN
        INCREMENT player2_wins
        IF player2_wins == 3 THEN
            PRINT "Player 2 wins the cake!"
            EXIT LOOP
IF player1_wins == 3 THEN
    PRINT "Player 1 wins the cake!"
ELSE IF player2_wins == 3 THEN
    PRINT "Player 2 wins the cake!"
ELSE
    PRINT "No player has won after 5 flips!"

Explanation:

This pseudocode follows these steps:

  1. Initialize counters for both players to keep track of their wins.

  2. Loop for a maximum of 5 flips.

  3. Within each loop iteration:

    1. Take input for the result of the coin flip.

    2. Update counters based on the result.

    3. Check if any player has won three times to announce the winner and early exit from the loop.

  4. Post loop check:Re-validate and announce the winner if any.Print a message if no player reaches 3 wins after 5 flips.


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