Write a program to find the sum of 1+1 / 8+ 1 / 27 ... .1 / n^{3}, where n is the number input by the user.
Question
Write a program to find the sum of $1+1 / 8+$ $1 / 27 \ldots . .1 / \mathrm{n}^{3}$, where $\mathrm{n}$ is the number input by the user.
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Answer
Here is a Python program to find the sum of $ 1 + \frac{1}{8} + \frac{1}{27} + \ldots + \frac{1}{n^3} $, where $ n $ is the number input by the user.
# Program to find the sum of 1 + 1/8 + 1/27 + ... + 1/n^3
def sum_of_series(n):
total_sum = 0
for i in range(1, n + 1):
total_sum += 1 / (i ** 3)
return total_sum
# Input from user
n = int(input("Enter the number n: "))
# Calculating the sum
result = sum_of_series(n)
# Displaying the result
print(f"The sum of the series for n = {n} is {result:.6f}")
This program defines a function sum_of_series(n)
that calculates the sum of the series. The user is prompted to enter a number $ n $, and the sum is calculated and displayed with 6 decimal precision.
Key points:
Function definition:
sum_of_series(n)
calculates the sum.User input: The program takes an integer input from the user.
Loop: A
for
loop iterates from 1 to $ n $ and computes the term-wise sum.Precision: The result is printed with six decimal places.
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